JHG JHXG电机引接线 耐高温

江苏春晨电缆有限公司生产JHG JHXG电机引接线 耐高温，

容抗反映了电容元件对交流电流阻碍能力的大小，它与C、f成反比。在相同电压作用下，按Q=CUc式，C越大，说明它容纳的电荷量越大，则它对电流的阻碍能力越小，电流就越大；若f越高，即电容的充电、放电过程越快，说明电容对电流的阻碍能力越小，电流也就越大。所以一个电容元件，在不同频率的正弦电压作用下，其对电流的阻碍作用是不同的，频率越高，Xc越小，电流越易通过。如果f=0，Xc=∞，即直流电流不能通过电容元件。直流电路中若有电容元件，电路在稳态时相当于开路。可见，在电路中，电容有隔直流通交流的作用。

The capacitive reactance reflects the capacity of the capacitor to block the AC current, which is inversely proportional to C and F. Under the same voltage, according to q = CUC formula, the larger C is, the greater the charge it holds, the smaller its blocking ability to current is, and the greater the current is; if f is higher, that is, the faster the charging and discharging process of capacitance is, the smaller the blocking ability of capacitance to current is, the greater the current is. Therefore, under the action of sinusoidal voltage with different frequency, the blocking effect of a capacitor on the current is different. The higher the frequency is, the smaller the XC is, and the easier the current is to pass through. If f = 0, XC = ∞, that is, the DC current cannot pass through the capacitor element. If there is capacitor in DC circuit, the circuit is equivalent to open circuit in steady state. It can be seen that in the circuit, capacitance has the function of isolating direct current and alternating current.

电容电路中的电流、电压波形如图b所示。

The current and voltage waveforms in the capacitor circuit are shown in Figure B.

电流与电压的相位关系

Phase relationship between current and voltage

电流与电压的相位关系是，电流超前电压90°，或电压落后电流90°。用相量形式表示，电流与电压的关系有：

The phase relationship between current and voltage is that current leads voltage by 90 ° or voltage lags current by 90 °. In the form of phasor, the relationship between current and voltage is as follows:

电流电压关系相量表示

Phasor representation of current voltage relationship

上相量式既表示了电压与电流的数值关系，又表示了它们的相位关系。-ji说明电压相量是在电流相量的基础上向顺时针方向旋转了90°，电压、电流之间的相位差角为90°。电流在相位上超前电压90°。JHG JHXG电机引接线 耐高温

The upphasor represents not only the numerical relationship between voltage and current, but also their phase relationship. -Ji indicates that the voltage phasor rotates 90 ° clockwise based on the current phasor, and the phase difference angle between voltage and current is 90 °. The current leads the voltage 90 ° in phase.

功率关系

Power relation

电容电路的瞬时功率：

Instantaneous power of capacitor circuit:

电容电路瞬时功率计算公式

Calculation formula of instantaneous power of capacitor circuit

瞬时功率pc的波形如图d所示，从图中可以看出，pc的幅值为UI，频率为2ω，即以2倍于电压的频率按正弦规律变化。当u、i同是正值或负值时，如图d中第1、第3个1/4周期，pc为正，说明在这个时段内，电容从电源吸收电能并将电能储存起来；当u、i中有一个是负值时，如图d中第2、第4个1/4周期，pc为负值，即在这个时段内电容将储存的电能送回电源。瞬时功率正、负半周曲线包围的面积相等，说明电容从电源吸收的能量等于它送回电源的能量，即：

The waveform of instantaneous power PC is shown in Figure D. from the figure, it can be seen that the amplitude of PC is UI, and the frequency is 2 ω, that is, the frequency that is twice the voltage changes according to the sine law. When u and I are both positive or negative, as shown in the first and third 1 / 4 cycles of figure D, PC is positive, indicating that during this period, the capacitor absorbs electric energy from the power supply and stores it; when one of u and I is negative, as shown in the second and fourth 1 / 4 cycles of figure D, PC is negative, that is to say, during this period, the capacitor will send the stored electric energy back to the power supply. The area surrounded by the positive and negative half cycle curves of instantaneous power is equal, which means that the energy absorbed by the capacitor from the power source is equal to the energy returned to the power source, that is:

纯电容不消耗能量，它只与电源不断地进行能量的交换。

Pure capacitance does not consume energy, it only exchanges energy with power supply continuously.

电容的平均功率为：

The average power of the capacitor is:

电容的平均功率计算公式

Calculation formula of average power of capacitor

平均功率为零只是说明电容不消耗有功功率，并不说明电容中没有功率。电容与电源之间有能量交换，所以瞬时功率并不等于零。瞬时功率的大值UI的乘积称为无功功率，用符号Qc表示，它反映了电容与电源交换能量的大规模。