进口说明IC693CPU323RR
IC693CPU323RR 如果Z′为偶数,则每极每相槽数:
q=Z1/(2pm)=Z′•t•m/(2pm)=(Z′/2)/(p/t)=(Z′/2)/p′=N/d (24)
同理,由于Z′与p′不可约,Z′/2与p′必不可约,即(Z′/2)/p′为简分数,那必然是N=Z′/2;d=p′=p/t,则单元电机个数为:
t=p/d (25)
另外由于Z′与p′不可约,Z′为偶数时,p′必为奇数,因此也可以把Z′为偶数的前提条件转化为d为奇数。即d为奇数时,可以把每相等分成两个相等的正负相带,此时即可以构成双层绕组,也可以构成单层绕组。
如果是双层绕组,一个单元电机可以构成两条并联支路,t个单元电机多可以构成2t条并联支路,即这种情况对双层绕组大并联支路数为:
amax=2t=2p/d (26)
如果是单层绕组,一个单元只能构成一条并联支路,t个单元电机多可以构成t条并联支路,即这种情况对单层绕组大并联支路数为:
amax=t=p/d (27)
IC693CPU323RR
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